Rabu, 04 Maret 2009

tugas order by induk



Scriptnya gini:


<html>


<body background="bg2.jpg">

<font size=16>Entry Data Siswa</font>
<br />
<hr>
Ketik data-data siswa dibawah ini :<br />
<br />
<br />
<form id="form1? name="form1? method="post" action="isisiswa.php">
<table>
<tr><td>Nama Siswa</td><td><input type="text" name="nama" id="nama" /></td></tr>

<tr><td>Nomor Induk</td><td><input type="text" name="induk" id="induk" /></td></tr>

<tr><td>Kelas</td><td><input type="text" name="kelas" id="kelas" /></td></tr>

</table>
<br />
<br />

<hr>
<input type="submit" name="Submit" id="Submit" value="Kirim" />
</form>
</body>

</html>







<html>
<body background="bg1.jpg">
<br>

<font size="5" ><center>DAFTAR SISWA</center><br />
</font>
<?php
$conn = mysql_connect("localhost","root","");
if (!$conn) {
echo "Could not connect to db";
exit(1);
}
$db = mysql_select_db("latihan",$conn);

$sqlText = "select * from siswa order by induk";
$result = mysql_query($sqlText);
echo "<table border=1 align=center >";
echo "<tr><td width=150><b><center>Nama Siswa</center></b></td>
<td width=150><b><center>Nomor Induk</center></b></td></b>
<td width=150><b><center>Kelas</center></b></td></b></tr>";

while($row=mysql_fetch_object($result))
{
echo "<tr><td>$row->nama</td><td align=center>$row->induk</td><td align=center>$row->kelas</td></tr>";
}

echo "</table>";
?>
</body>
</html>


isisiswa.php

<html>
<head>
<title>Input Data dari Form ke MySQL</title>
</head>

<body>
<?php
$nama = $_POST['nama'];
$induk = $_POST['induk'];
$kelas = $_POST['kelas'];

$conn = mysql_connect("localhost","root","");
if (!$conn) {
echo "Could not connect to db";
exit(1);
}
$db = mysql_select_db("latihan",$conn);

$sqlText = "insert into siswa(nama, induk, kelas)
values('$nama','$induk','$kelas')";
mysql_query($sqlText);


?>Data telah dimasukkan dalam database<br />
</body>
</html>